Question

en: (\triangle abc) a midsegment of (\triangle abc) is parallel to a side of (\triangle abc). 2 what is the reason for statement 3 in this proof? a. using point - slope formula b. definition of parallel lines c. transitive property of equality d. reflexive property of equality e. definition of midpoint

Explanation:

The problem is about geometric proof. The Transitive Property of Equality states that if \(a = b\) and \(b = c\), then \(a = c\). In a geometric proof context, if two segments (or slopes, if using coordinate - geometry approach for parallel lines) are each equal to a third segment (or slope), this property can be used to establish equality (which is relevant for showing parallelism in some proof - setups). The point - slope formula is for writing the equation of a line, the definition of parallel lines is about lines that never meet, the reflexive property is \(a=a\), and the definition of midpoint is about a point that divides a segment into two equal parts.

Answer:

C. Transitive Property of Equality