Question

emery tracks the number of successful basketball shots made during practice. every 5 minutes, she records the number of shots she has made. she starts strong but begins to slow down as practice continues. question 1 2 points during which time interval did emerys rate of successful shots decrease? 10 - 20 minutes 0 - 10 minutes 0 - 20 minutes her rate stayed the same

Explanation:

Step1: Calculate the rate for 0 - 10 minutes

The rate (slope) formula is \(m=\frac{y_2 - y_1}{x_2 - x_1}\). For the interval \(0 - 10\) minutes, \(x_1 = 0,y_1=0,x_2 = 10,y_2 = 20\). Then \(m_1=\frac{20 - 0}{10 - 0}=2\) (shots per minute).

Step2: Calculate the rate for 10 - 20 minutes

For the interval \(10 - 20\) minutes, assume at \(x = 20\), \(y\) is approximately \(28\) (from the graph). \(x_1 = 10,y_1 = 20,x_2=20,y_2 = 28\). Then \(m_2=\frac{28 - 20}{20 - 10}=\frac{8}{10}=0.8\) (shots per minute).

Since \(m_1 = 2>m_2=0.8\), the rate decreased in the \(10 - 20\) - minute interval.

Answer:

10 - 20 minutes