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Question
if ∠efg and ∠lmn are a linear pair, and m∠efg is equal to 134°, then what is m∠lmn? m∠lmn = ?°
Step1: Recall linear - pair property
Linear - pair angles sum to $180^{\circ}$.
Let $m\angle EFG = 134^{\circ}$ and $m\angle LMN=x$. Then $m\angle EFG + m\angle LMN=180^{\circ}$.
Step2: Solve for $m\angle LMN$
$x = 180 - 134$.
$x = 46$.
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$46$