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edna brought 4 pies to a party. at the end of the evening, 1 5/8 pie wa…

Question

edna brought 4 pies to a party. at the end of the evening, 1 5/8 pie was left over. how much pie did the guests eat?

Explanation:

Step1: Convert mixed numbers to improper fractions

Edna brought \(4\) pies, which is \(\frac{4\times8}{8}=\frac{32}{8}\) pies. The leftover pie is \(1\frac{5}{8}=\frac{1\times8 + 5}{8}=\frac{13}{8}\) pies.

Step2: Subtract the leftover from the total

The amount of pie guests ate is \(\frac{32}{8}-\frac{13}{8}=\frac{32 - 13}{8}=\frac{19}{8}\). Convert \(\frac{19}{8}\) to a mixed number: \(19\div8 = 2\) with a remainder of \(3\), so \(\frac{19}{8}=2\frac{3}{8}\)

Answer:

\(2\frac{3}{8}\) pies (assuming there was a typo in the options and the intended correct - option is \(2\frac{3}{8}\) based on the calculation. If we follow the given options strictly and assume it's a calculation error in the problem - setup, we need to re - check. But based on the standard subtraction of \(4-1\frac{5}{8}\): \(4 = 3\frac{8}{8}\), \(3\frac{8}{8}-1\frac{5}{8}=2\frac{3}{8}\))