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Question
an eagle that has a mass of 4.5 kg is spotted 5 m above a lake. it flies up to its nest in a tree at a height of 25 m. how much gravitational potential energy did the eagle gain?
221 j
882 j
1103 j
1377 j
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- First, recall the gravitational - potential - energy formula:
- The formula for gravitational potential energy is $U = mgh$, where $m$ is the mass, $g$ is the acceleration due to gravity ($g=9.8\ m/s^{2}$), and $h$ is the height.
- The change in gravitational potential energy $\Delta U=mg\Delta h$.
- Then, find the change in height $\Delta h$:
- The initial height $h_1 = 5\ m$ and the final height $h_2 = 25\ m$. So, $\Delta h=h_2 - h_1=25 - 5=20\ m$.
- The mass of the eagle $m = 4.5\ kg$ and $g = 9.8\ m/s^{2}$.
- Next, calculate the change in gravitational potential energy:
- Substitute the values into the formula $\Delta U=mg\Delta h$.
- $\Delta U=4.5\times9.8\times20$.
- First, $4.5\times9.8 = 44.1$.
- Then, $44.1\times20=882\ J$.
The answer is 882 J. So the correct option is: 882 J.