Question

each shopper pushes with the same force. order the shoppers purchases to show the size of the acceleration each cart will have. larger acceleration 20 cans of beans 5 boxes of cereal 2 bags of grapes 10 bottles of juice

Explanation:

Step1: Calculate the total mass for each purchase

• For \(20\) cans of beans: \(20\times500 = 10000\) g
• For \(5\) boxes of cereal: \(5\times30=150\) g
• For \(2\) bags of grapes: \(2\times900 = 1800\) g
• For \(10\) bottles of juice: \(10\times400=4000\) g

Step2: Use Newton's second law \(F = ma\) (since \(F\) is constant, \(a=\frac{F}{m}\), acceleration is inversely proportional to mass)

• The order of mass from smallest to largest: \(150\) g (\(5\) boxes of cereal) \(<1800\) g (\(2\) bags of grapes) \(<4000\) g (\(10\) bottles of juice) \(<10000\) g (\(20\) cans of beans)
• Since \(a=\frac{F}{m}\) ( \(F\) is constant), the order of acceleration (which is inversely proportional to mass) from largest to smallest is: \(5\) boxes of cereal \(>2\) bags of grapes \(>10\) bottles of juice \(>20\) cans of beans

Answer:

\(5\) boxes of cereal \(>2\) bags of grapes \(>10\) bottles of juice \(>20\) cans of beans