Question

each full bag of last week? show your thinking. 2\frac{1}{6}+3\frac{1}{2}+2\frac{1}{4}+3\frac{2}{3}=

Explanation:

Step1: Convert mixed - numbers to improper fractions

$2\frac{1}{6}=\frac{2\times6 + 1}{6}=\frac{13}{6}$, $3\frac{1}{2}=\frac{3\times2+1}{2}=\frac{7}{2}$, $2\frac{1}{4}=\frac{2\times4 + 1}{4}=\frac{9}{4}$, $3\frac{2}{3}=\frac{3\times3+2}{3}=\frac{11}{3}$

Step2: Find a common denominator

The least common multiple of 6, 2, 4, and 3 is 12.
$\frac{13}{6}=\frac{13\times2}{6\times2}=\frac{26}{12}$, $\frac{7}{2}=\frac{7\times6}{2\times6}=\frac{42}{12}$, $\frac{9}{4}=\frac{9\times3}{4\times3}=\frac{27}{12}$, $\frac{11}{3}=\frac{11\times4}{3\times4}=\frac{44}{12}$

Step3: Add the fractions

$\frac{26}{12}+\frac{42}{12}+\frac{27}{12}+\frac{44}{12}=\frac{26 + 42+27+44}{12}=\frac{139}{12}$

Step4: Convert back to a mixed - number

$139\div12 = 11$ with a remainder of 7, so $\frac{139}{12}=11\frac{7}{12}$

Answer:

$11\frac{7}{12}$