Question

dwayne is selling hamburgers and cheeseburgers. he has 100 burger buns. each hamburger sells for $3, and each cheeseburger sells for $3.50. which system of inequalities represents the number of hamburgers, h, and the number of cheeseburgers, c, he must sell to have sales of at least $80?
h + c ≤ 80
3h + 3.5c ≤ 100
h + c ≤ 80
3h + 3.5c ≥ 100
h + c ≤ 100
3h + 3.5c ≤ 80
h + c ≤ 100
3h + 3.5c ≥ 80

Explanation:

Step1: Analyze the bun constraint

The total number of hamburgers (\(h\)) and cheeseburgers (\(c\)) can't exceed the number of buns, which is 100. So, \(h + c \leq 100\).

Step2: Analyze the sales constraint

Each hamburger sells for \$3, so total revenue from hamburgers is LXI0. Each cheeseburger sells for \$3.50, so total revenue from cheeseburgers is \(3.5c\). The sales need to be at least \$80, meaning the total revenue \(3h + 3.5c\) must be greater than or equal to 80. So, \(3h + 3.5c \geq 80\).

Answer:

\(h + c \leq 100\)
\(3h + 3.5c \geq 80\) (the last option among the given choices)