Question

divide. if there is a remainder, include it as a simplified fraction.\\((-12g^{3}+12g^{2}-8g)\div4g^{2}\\)

Explanation:

Step1: Split the polynomial division

$\frac{-12g^3 + 12g^2 - 8g}{4g^2} = \frac{-12g^3}{4g^2} + \frac{12g^2}{4g^2} - \frac{8g}{4g^2}$

Step2: Simplify each term

$\frac{-12g^3}{4g^2} = -3g$, $\frac{12g^2}{4g^2} = 3$, $\frac{8g}{4g^2} = \frac{2}{g}$

Step3: Combine simplified terms

$-3g + 3 - \frac{2}{g}$

Answer:

$-3g + 3 - \frac{2}{g}$