Question

distance
distance is the

of a path taken.
it identifies how much ground
an object has

ex: jonathan threw 2 passes
at 50yds and 30 yds. what
was the distance the ball traveled?
displacement

of a straight line
between 2 points

path between the
start and end points

is \0\ when an object ends
in the same place

Explanation:

Step1: Recall the concept of distance

Distance is the total length of a path taken. It identifies how much ground an object has covered.

Step2: Calculate the distance of the ball

For the example, we use the formula for distance (since distance is the sum of the lengths of the paths). If the two passes are \(d_1 = 50\) yds and \(d_2=30\) yds, then the distance \(D=d_1 + d_2\).
Substitute the values: \(D = 50+30\)

Step3: Simplify the expression

\(D=80\) yds

For displacement:

Step1: Recall the concept of displacement

Displacement is the length of a straight - line between 2 points. It is the shortest path between the start and end points. It is “0” when an object ends in the same place it started.

Answer:

For the distance example, the ball traveled a distance of 80 yds. For displacement: length (for the first blank in displacement), shortest (for the second blank in displacement)