Question

difference of perfect squares (level 1)
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factor completely.
81 - 100x²

Explanation:

Step1: Identify the form of difference of squares

The expression \(81 - 100x^{2}\) can be written as \(9^{2}-(10x)^{2}\), which is in the form of \(a^{2}-b^{2}\) where \(a = 9\) and \(b=10x\).

Step2: Apply the difference of squares formula

The formula for the difference of squares is \(a^{2}-b^{2}=(a + b)(a - b)\). Substituting \(a = 9\) and \(b = 10x\) into the formula, we get \((9+10x)(9 - 10x)\).

Answer:

\((9 + 10x)(9 - 10x)\)