Question

$\overline{ij}$ is a diameter of the circle. the circumference of the circle is 113.22. find the length of $\overline{ij}$, rounding to the nearest tenth.

Explanation:

Step1: Recall the formula for the circumference of a circle

The formula for the circumference \(C\) of a circle is \(C=\pi d\), where \(d\) is the diameter.

Step2: Solve for the diameter \(d\)

We know that \(C = 113.22\) and \(\pi\approx3.14\). Substitute into the formula \(d=\frac{C}{\pi}\).
So \(d=\frac{113.22}{3.14}\).

Step3: Calculate the value of \(d\)

\(\frac{113.22}{3.14}=36.057325\).

Step4: Round to the nearest tenth

Rounding \(36.057325\) to the nearest tenth gives \(36.1\).

Answer:

\(36.1\)