QUESTION IMAGE
Question
d)
diagram of two parallel lines cut by a transversal, with one angle labeled 109° and another angle labeled z°
z =
Step1: Identify Parallel Lines and Transversal
Lines A and B are parallel, cut by a transversal. The given angle (109°) and angle \( z \) are same - side interior angles? Wait, no, actually, the 109° angle and the angle adjacent to \( z \) (vertical or corresponding?) Wait, let's see: the 109° angle and \( z \) are same - side interior angles? No, wait, when two parallel lines are cut by a transversal, same - side interior angles are supplementary. Wait, the 109° angle and the angle that is supplementary to \( z \)? Wait, no, looking at the diagram, the 109° angle and \( z \): since lines A and B are parallel, the angle adjacent to 109° (let's say the angle on the same side of the transversal as \( z \)) and \( z \) are supplementary? Wait, no, actually, the 109° angle and \( z \) are same - side interior angles? Wait, no, let's think again. The sum of same - side interior angles is 180°. Wait, the 109° angle and \( z \): if we consider the parallel lines A and B, and the transversal, then \( z \) and the angle that is 109°'s supplementary? Wait, no, the 109° angle and \( z \) are same - side interior angles? Wait, no, let's check the diagram. The 109° is on line B, and \( z \) is on line A, on the same side of the transversal. So same - side interior angles are supplementary. So \( z+ 109^{\circ}=180^{\circ}\)? Wait, no, wait, maybe the 109° angle and \( z \) are corresponding? No, the shaded angle \( z \) and the angle adjacent to 109° (the one that is vertical to the angle supplementary to 109°). Wait, let's calculate: if two parallel lines are cut by a transversal, same - side interior angles are supplementary. So the angle on line B that is same - side interior with \( z \) is 109°, so \( z + 109^{\circ}=180^{\circ}\)? Wait, no, that would be if they are same - side interior. Wait, no, actually, the 109° angle and \( z \) are same - side interior angles, so \( z=180 - 109\)? Wait, no, wait, maybe I got it wrong. Wait, the 109° angle and \( z \): let's see, the 109° angle is on line B, and \( z \) is on line A. The transversal cuts them. So the angle that is vertical to the angle next to 109°: no, let's do the math. The sum of \( z \) and 109° should be 180° because they are same - side interior angles. So \( z = 180-109\).
Step2: Calculate \( z \)
\( z=180 - 109=71\)? Wait, no, wait, that can't be. Wait, no, maybe the 109° angle and \( z \) are corresponding angles? No, the diagram shows that the 109° is on the lower line (B) and \( z \) is on the upper line (A), on the same side of the transversal. Wait, maybe I made a mistake. Wait, no, the correct approach: when two parallel lines are cut by a transversal, same - side interior angles are supplementary. So if the 109° angle and \( z \) are same - side interior angles, then \( z + 109=180\), so \( z = 180 - 109 = 71\)? Wait, no, that's not right. Wait, maybe the 109° angle and \( z \) are alternate interior angles? No, alternate interior angles are equal. Wait, maybe the 109° angle and \( z \) are same - side exterior angles? No, same - side exterior angles are also supplementary. Wait, no, let's look at the diagram again. The 109° angle is on line B, and \( z \) is on line A, on the same side of the transversal. So they are same - side interior angles, so they should be supplementary. So \( z=180 - 109 = 71\)? Wait, no, that's incorrect. Wait, maybe the 109° angle and \( z \) are corresponding angles. Wait, no, the diagram: the 109° is on the lower line, and \( z \) is on the upper line, on the same side of the transversal. Wait, maybe I mixed up. Wait, the correct formu…
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\( z = 71 \)