QUESTION IMAGE
Question
the diagram shows a triangle. angles are 12y, 16y+12°, 12y+8°. what is the value of y? y = \boxed{}°
Step1: Recall triangle angle sum
The sum of angles in a triangle is \(180^\circ\). So, we add the three angles: \(12y + (12y + 8^\circ) + (16y + 12^\circ) = 180^\circ\).
Step2: Combine like terms
Combine the \(y\)-terms and constant terms: \(12y + 12y + 16y + 8 + 12 = 180\), which simplifies to \(40y + 20 = 180\).
Step3: Solve for \(y\)
Subtract 20 from both sides: \(40y = 180 - 20 = 160\). Then divide by 40: \(y = \frac{160}{40} = 4\).
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\(y = 4\)