Question

the diagram shows a 15-kg box resting on a wedge which has an angle of inclination of 30° and a coefficient of friction of 0.15. which equation correctly gives the value of ( f_f ), the force due to friction?
a ( f_f = 0.15 f_n )
b ( f_f = 0.15 f_g )
c ( f_f = 0.15 f_parallel )
d ( f_f = 0.15 f f_perp )

Explanation:

Step1: Recall Friction Formula

Frictional force \( F_f = \mu F_N \), where \( \mu \) is coefficient of friction, \( F_N \) is normal force.

Step2: Identify Variables

Given \( \mu = 0.15 \), so \( F_f = 0.15 F_N \). Check options: Option A is \( F_f = 0.15 F_N \), matching the formula.

Answer:

A. \( F_f = 0.15F_N \)