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in the diagram of the circle shown below: • \\( \\overline { a b } \\) …

Question

in the diagram of the circle shown below:

  • \\( \overline { a b } \\) and \\( \overline { a c } \\) are tangent to the circle
  • \\( m \widehat { b c } = 95 ^ { \circ } \\)
  • \\( m \widehat { b d c } = 265 ^ { \circ } \\)

which statement describes how to calculate the measure of \\( m \angle b a c \\) ?
\\( m \angle b a c \\) is a third of the sum of the measures of \\( m \widehat { b d c } \\) and \\( m \widehat { b c } \\), or \\( 120 ^ { \circ } \\).
\\( m \angle b a c \\) is a fourth of the sum of the measures of \\( m \widehat { b d c } \\) and \\( m \widehat { b c } \\), or \\( 90 ^ { \circ } \\).
\\( m \angle b a c \\) is a third of the difference of the measures of \\( m \widehat { b d c } \\) and \\( m \widehat { b c } \\), or \\( 56 ^ { \circ } \\).
\\( m \angle b a c \\) is half of the difference of the measures of \\( m \widehat { b d c } \\) and \\( m \widehat { b c } \\), or \\( 85 ^ { \circ } \\).

Explanation:

Step1: Recall the formula for the angle formed by two tangents

The measure of an angle formed by two tangents drawn from an external point to a circle is half the difference of the measures of the intercepted arcs. The formula is \(m\angle BAC=\frac{1}{2}(m\widehat{BDC}-m\widehat{BC})\).

Step2: Substitute the given values

Given \(m\widehat{BDC} = 265^{\circ}\) and \(m\widehat{BC}=95^{\circ}\). Then \(m\angle BAC=\frac{1}{2}(265 - 95)\).

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Answer:

\(m\angle BAC\) is half of the difference of the measures of \(m\widehat{BDC}\) and \(m\widehat{BC}\), or \(85^{\circ}\).