the diagram below is a right rectangular prism. all the angles shown measure 90°. name two segments drawn on the diagram below that are skew.

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# Brief Explanations:
Skew lines are lines that are not parallel and do not intersect, and they lie in different planes. In a right rectangular prism (a box - like shape), consider the edges. For example, segment $TW$ and segment $PQ$: $TW$ is on the top face and $PQ$ is on the bottom face, they are not parallel and do not intersect. Another example could be $TP$ and $VQ$: $TP$ is a vertical edge on the left - hand side and $VQ$ is a vertical edge on the right - hand side? No, wait, $TP$ and $VQ$ are parallel. Let's take $TW$ and $PQ$ or $TW$ and $SR$ (if $SR$ is an edge, but from the diagram labels: let's assume the vertices are $P, Q, R, S$ (bottom face) and $T, U, V, W$ (top face) with $T$ above $P$, $U$ above $Q$, $V$ above $R$, $W$ above $S$. So $TW$ is from $T$ to $W$, $PQ$ is from $P$ to $Q$. $TW$ and $PQ$ are skew because they are in different planes, not parallel, and do not intersect. Also, $TP$ (from $T$ to $P$) and $VQ$ (from $V$ to $Q$): no, $TP$ and $VQ$ are parallel. Wait, $TP$ and $UQ$? No, $UQ$ is vertical? Wait, maybe $TW$ and $PQ$, or $TW$ and $QR$. Let's confirm the definition: Skew lines are non - coplanar, non - parallel, non - intersecting lines. So in the prism, edges like $TW$ (top front - top back) and $PQ$ (bottom front - bottom back) are skew. Or $TP$ (front left vertical) and $VQ$ (back right vertical)? No, $TP$ and $VQ$ are skew? Wait, $TP$ is from $T$ to $P$ (vertical), $VQ$ is from $V$ to $Q$ (vertical). Wait, no, if the prism is right, $TP$ and $VQ$ are parallel. Let's take $TW$ (top edge, left - back) and $PQ$ (bottom edge, front - right? No, $PQ$ is front - bottom, $TW$ is top - left - back. So $TW$ and $PQ$ are in different planes, not parallel, not intersecting. Another example: $TW$ and $SR$ (if $SR$ is bottom - back edge). Or $TP$ and $VQ$ is wrong, let's take $TW$ and $PQ$ as one pair, and $TP$ and $VQ$ is parallel, so not skew. Wait, $TP$ and $UQ$: $TP$ is vertical, $UQ$ is vertical, parallel. So a correct pair is $TW$ and $PQ$, or $TW$ and $QR$ ( $QR$ is bottom - front - right to bottom - back - right? No, $QR$ is on the bottom face. Wait, $TW$ is on the top face (connecting $T$ (above $P$) to $W$ (above $S$)), $PQ$ is on the bottom face (connecting $P$ to $Q$). They are not parallel (direction of $TW$ is from front - left - top to back - left - top? Wait, no, if $T$ is above $P$, $W$ is above $S$, so $TW$ is a horizontal edge on the top face, parallel to $SP$? No, $SP$ is a bottom edge. Wait, maybe I got the orientation wrong. Let's re - orient: Let the bottom face be $P - Q - R - S$ (in order, so $P$ to $Q$ is front, $Q$ to $R$ is right, $R$ to $S$ is back, $S$ to $P$ is left). Top face is $T - U - V - W$, with $T$ above $P$, $U$ above $Q$, $V$ above $R$, $W$ above $S$. So edges: $TP$ (vertical, front - left), $UQ$ (vertical, front - right), $VR$ (vertical, back - right), $WS$ (vertical, back - left). Horizontal top edges: $TU$ (front - top), $UV$ (right - top), $VW$ (back - top), $WT$ (left - top). Horizontal bottom edges: $PQ$ (front - bottom), $QR$ (right - bottom), $RS$ (back - bottom), $SP$ (left - bottom). Now, skew lines: $WT$ (left - top) and $QR$ (right - bottom): they are not parallel ( $WT$ is left - top horizontal, $QR$ is right - bottom horizontal, different directions), not intersecting, and in different planes. Or $TP$ (front - left vertical) and $VW$ (back - top horizontal): not parallel, not intersecting, different planes. But a simple pair is $WT$ (or $TW$) and $PQ$: $TW$ (from $T$ to $W$, left - top horizontal) and $PQ$ (from $P$ to $Q$, front - bottom horizontal). They are non - coplanar, non - parallel, non - intersecting.
# Answer:
Two skew segments could be $\boldsymbol{TW}$ and $\boldsymbol{PQ}$ (or other valid pairs like $\boldsymbol{TW}$ and $\boldsymbol{QR}$, $\boldsymbol{TP}$ and $\boldsymbol{VQ}$ is incorrect as they are parallel, but $\boldsymbol{TW}$ and $\boldsymbol{PQ}$ is a valid example).

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