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determining side lengths of special right triangles. what are the lengt…

Question

determining side lengths of special right triangles. what are the lengths of the other two sides of the triangle? ac = 5\sqrt{3} and bc = 5. ac = 5 and bc = 5\sqrt{5}. ac = 5 and bc = 5\sqrt{3}.

Explanation:

Step1: Recall 30 - 60 - 90 triangle ratio

In a 30 - 60 - 90 right - triangle, if the hypotenuse \(c\) is given, and the sides are in the ratio \(1:\sqrt{3}:2\) (where the side opposite the 30° angle is \(a\), the side opposite the 60° angle is \(b\), and the hypotenuse is \(c\), \(a:x:2x\) with \(c = 2x\)).

Step2: Find the side opposite 30°

Given hypotenuse \(AB = 10\). Let the side opposite the 30° angle (\(AC\)) be \(x\). Since \(c = 2x\) and \(c=10\), then \(2x = 10\), so \(x=\frac{10}{2}=5\).

Step3: Find the side opposite 60°

The side opposite the 60° angle (\(BC\)) is \(\sqrt{3}x\). Substituting \(x = 5\), we get \(BC = 5\sqrt{3}\).

Answer:

AC = 5 and BC = 5√3