determine the magnitude and direction of the force between two parallel wires 25 m long and 3.0 cm apart, each carrying 25 a in the same direction. the force on each wire will be repulsive. the force on each wire will be attractive. the wires will not interact. previous answers correct part b determine the magnitude of the force between two parallel wires. express your answer to two significant figures and include the appropriate units.

Question

Accepted Answer

# Explanation:
## Step1: Recall force formula
The formula for the force between two parallel current - carrying wires is $F = \frac{\mu_0I_1I_2L}{2\pi r}$, where $\mu_0=4\pi\times 10^{- 7}\ T\cdot m/A$, $I_1 = I_2=25\ A$, $L = 25\ m$, and $r=3.0\ cm=0.03\ m$.
## Step2: Substitute values
Substitute the given values into the formula:
$$
\begin{align*}
F&=\frac{\mu_0I_1I_2L}{2\pi r}\
&=\frac{4\pi\times 10^{-7}\times25\times25\times25}{2\pi\times0.03}\
&=\frac{2\times10^{-7}\times25\times25\times25}{0.03}
\end{align*}
$$
## Step3: Calculate the force
$$
\begin{align*}
F&=\frac{2\times10^{-7}\times25\times25\times25}{0.03}\
&=\frac{2\times10^{-7}\times15625}{0.03}\
&=\frac{31250\times10^{-7}}{0.03}\
&\approx0.10\ N
\end{align*}
$$

# Answer:
$0.10\ N$

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QUESTION IMAGE

Question

Explanation:

Step1: Recall force formula

Step2: Substitute values

Step3: Calculate the force

Answer: