Question

determine the center and radius of the circle $(x + 2)^2 + y^2 = 16$. enter the center as a point $(a,b)$. the center is . the radius is .

Explanation:

Step1: Recall circle - standard form

The standard form of a circle is $(x - h)^2+(y - k)^2=r^2$, where $(h,k)$ is the center and $r$ is the radius.

Step2: Rewrite the given equation

The given equation is $(x + 2)^2+y^2 = 16$, which can be written as $(x-(-2))^2+(y - 0)^2=4^2$.

Answer:

The center is $(-2,0)$.
The radius is $4$.