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Question
describe the rotation in mapping notation. enter the correct answer in the boxes. hide hints next hint use the graph and coordinates you found in parts a and (x,y) →(□, □) 7 8 9 4 5 6 1 2 3
To determine the rotation mapping, we typically consider common rotations (90°, 180°, 270°) about the origin. Let's assume a 90° counterclockwise rotation (a common case) or 90° clockwise, 180°, etc. But since the graph has points (we can infer from the numbers, maybe a figure with coordinates). Wait, maybe the original figure and its rotated image. Let's recall rotation rules:
- 90° counterclockwise: \((x, y) \to (-y, x)\)
- 90° clockwise: \((x, y) \to (y, -x)\)
- 180°: \((x, y) \to (-x, -y)\)
- 270° counterclockwise (same as 90° clockwise): \((x, y) \to (y, -x)\)
- 270° clockwise (same as 90° counterclockwise): \((x, y) \to (-y, x)\)
But since the problem refers to "Parts A and B" (not shown), but maybe it's a 90° clockwise or counterclockwise. Wait, maybe the graph is a figure, like a polygon, and after rotation, the coordinates change. Let's assume a common case, say 90° clockwise rotation: \((x, y) \to (y, -x)\), but maybe the center is the origin. Alternatively, if it's a 180° rotation, \((x, y) \to (-x, -y)\). But since the user's graph has numbers 1,2,3,4,5,6,7,8,9, maybe a grid. Wait, maybe the original figure has coordinates, and after rotation, we can find the mapping.
Wait, maybe the problem is about a 90° counterclockwise rotation, so the mapping is \((x, y) \to (-y, x)\), or 90° clockwise \((x, y) \to (y, -x)\). But since the user's input is a bit unclear, but let's assume a common rotation. Wait, maybe the graph is a square or triangle. Alternatively, maybe the rotation is 90° clockwise, so the mapping is \((x, y) \to (y, -x)\), but if the center is the origin. Alternatively, if it's a 180° rotation, \((x, y) \to (-x, -y)\).
But since the problem is about rotation mapping, let's recall the standard rotation rules. Let's suppose the rotation is 90° clockwise: the rule is \((x, y) \to (y, -x)\). Or 90° counterclockwise: \((x, y) \to (-y, x)\).
Wait, maybe the original figure has coordinates, and after rotation, we can find the mapping. For example, if a point (1,0) rotates 90° counterclockwise, it becomes (0,1), so \((x,y) \to (-y, x)\). If (1,0) rotates 90° clockwise, it becomes (0,-1), so \((x,y) \to (y, -x)\).
But since the user's problem is to describe the rotation in mapping notation, and the boxes are for the x and y components. Let's assume a 90° counterclockwise rotation: the mapping is \((x, y) \to (-y, x)\). So the first box is \(-y\) and the second is \(x\). Or if it's 90° clockwise, \((x, y) \to (y, -x)\), so first box \(y\), second \(-x\).
Alternatively, if it's a 180° rotation, \((x, y) \to (-x, -y)\), so first box \(-x\), second \(-y\).
But since the problem refers to "Parts A and B" (not shown), maybe the original coordinates and rotated coordinates lead to a specific mapping. For example, if a point (a, b) becomes (b, -a) after rotation, then it's 90° clockwise. If it becomes (-b, a), then 90° counterclockwise.
Assuming a common case, let's take 90° clockwise rotation: the mapping is \((x, y) \to (y, -x)\). So the answer would be \((x, y) \to (y, -x)\), so the first box is \(y\) and the second is \(-x\). Or if it's 90° counterclockwise, \(-y\) and \(x\).
But since the user's graph has numbers 1,2,3,4,5,6,7,8,9, maybe it's a grid with points, like (1,1), (2,1), etc. Wait, maybe the original figure is a polygon, and after rotation, the coordinates change. For example, if the original point is (2,1) and after rotation it's (1,-2), then it's 90° clockwise, so mapping (x,y)→(y, -x).
Alternatively, maybe the rotation is 90° counterclockwise, so (x,y)→(-y, x). Let's confirm with an example: (1,0) rot…
Step1: Recall rotation rules (90° counterclockwise)
The rule for a 90° counterclockwise rotation about the origin is \((x, y) \to (-y, x)\).
Step2: Apply the rule to the mapping notation
Substitute the rotation rule into the mapping \((x, y) \to (\square, \square)\).
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\((x, y) \to (-y, x)\) (So the first box is \(-y\) and the second is \(x\))