Question

for a data set of the pulse rates for a sample of adult females, the lowest pulse rate is 39 beats per minute, the mean of the listed pulse rates is \\( \overline { x } = 72.0 \\) beats p standard deviation is \\( s = 10.6 \\) beats per minute.
a. what is the difference between the pulse rate of 39 beats per minute and the mean pulse rate of the females?
b. how many standard deviations is that (the difference found in part (a))?
c. convert the pulse rate of 39 beats per minutes to a z score.
d. if we consider pulse rates that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the pulse rate of 39 beats per minu

a. the difference is 33 beats per minute.
(type an integer or a decimal. do not round.)
b. the difference is \\( \square \\) standard deviations.
(round to two decimal places as needed.)

Explanation:

Step1: Calculate the number of standard deviations

We know the difference from part (a) is \(d = 33\) and the standard deviation \(s=10.6\). The formula to find the number of standard deviations is \(\frac{d}{s}\).

$$ \frac{33}{10.6} $$

Step2: Perform the division

$$ \frac{33}{10.6}\approx3.11 $$

Answer:

\(3.11\)