Question

a cylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. if the basin is completely filled with water, how much water will it hold? round the answer to the nearest tenth of a foot. ft³

Explanation:

Step1: Find the radius of the cylinder

The diameter \(d = 5\) feet. The radius \(r=\frac{d}{2}=\frac{5}{2}=2.5\) feet.

Step2: Use the formula for the volume of a cylinder

The formula for the volume of a cylinder is \(V=\pi r^{2}h\). Here, \(r = 2.5\) feet and \(h=2\) feet.
Substitute the values into the formula: \(V=\pi\times(2.5)^{2}\times2\).
First, calculate \((2.5)^{2}=6.25\). Then \(V=\pi\times6.25\times 2=12.5\pi\).
Using \(\pi\approx3.14\), we get \(V = 12.5\times3.14=39.25\) cubic feet.

Answer:

\(39.3\) \(ft^{3}\)