Question

1. if a cycling club organized a 72-km bike tour, and it took 5 h 15 min to complete, correct to the nearest tenth, the average speed of the cyclists is equal to ______ km/h ? \\(\left( s=\frac{d}{t} \

ight)\\)

Explanation:

Step1: Convert time to hours

15 minutes is $\frac{15}{60} = 0.25$ hours. So 5 h 15 min is $5 + 0.25 = 5.25$ hours.

Step2: Use speed formula

The formula for speed is $s=\frac{d}{t}$, where $d = 72$ km and $t = 5.25$ h. Substitute the values: $s=\frac{72}{5.25}$.

Step3: Calculate the speed

$\frac{72}{5.25} \approx 13.714\cdots$

Step4: Round to nearest tenth

Rounding $13.714\cdots$ to the nearest tenth gives $13.7$.

Answer:

13.7