Question

cross a parent that is homozygous recessive for both traits (bbee) with a dihybrid (bbee).
first, draw a punnett square in your notes.
for each offspring in the punnett square,
determine the phenotype.
in other words, what are the fur color and eye
color?
finally, use that information to fill in the
predicted fraction of each phenotype in the data
table below.

Explanation:

Step1: Determine gametes

The homozygous recessive parent (bbee) can only produce \( be \) gametes. The dihybrid parent (BbEe) can produce \( BE \), \( Be \), \( bE \), and \( be \) gametes.

Step2: Create Punnett square

	\( BE \)	\( Be \)	\( bE \)	\( be \)

Step3: Determine phenotypes

• \( BbEe \): Black fur (B) and black eyes (E)
• \( Bbee \): Black fur (B) and red eyes (ee)
• \( bbEe \): White fur (bb) and black eyes (E)
• \( bbee \): White fur (bb) and red eyes (ee)

Step4: Calculate fractions

Since there are 4 possible offspring genotypes (each with equal probability in a 1 - to - 1 cross), each phenotype has a fraction of \( \frac{4}{16} \) (because \( 4\times4 = 16 \) total cells in a Punnett square representation of this 1x4 cross conceptually, and each unique genotype appears 4 times).

Answer:

Black Fur and Black Eyes: \( 4/16 \)
Black Fur and Red Eyes: \( 4/16 \)
White Fur and Black Eyes: \( 4/16 \)
White Fur and Red Eyes: \( 4/16 \)