Question

coordinate proofs practice
complete this assessment to review what youve learned. it will not count toward your grade
the center of circle ( c ) is at ( (6,2) ), with a radius of 5. in order to prove that point ( d(6,-3) ) lies on the circle, what does the length of segment ( overline{cd} ) need to be? (1 point)
segment ( overline{cd} ) must have a length of
check answer remaining attempts : 3

Explanation:

Step1: Recall circle point condition

A point lies on a circle if its distance from the center equals the radius.

Step2: Calculate distance CD

Use distance formula: $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$. Substitute $C(6,2)$ and $D(6,-3)$:
$d = \sqrt{(6-6)^2 + (-3-2)^2} = \sqrt{0 + (-5)^2} = \sqrt{25} = 5$.

Step3: Compare to radius

The radius is 5, so CD must be 5.

Answer:

5