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construct the truth - table for the following: 1) $(p\\vee q)\\wedge\ e…

Question

construct the truth - table for the following:

  1. $(p\vee q)\wedge\

eg(p\wedge q)$

  1. $(p\

ightarrow q)\longleftrightarrow(\
eg p\vee q)$

Explanation:

Step1: List all possible truth - value combinations

We have two propositional variables \(P\) and \(Q\). So, there are \(2^2 = 4\) possible combinations: \((T,T)\), \((T,F)\), \((F,T)\), \((F,F)\).

Step2: Calculate \(P\vee Q\) values

The disjunction \(P\vee Q\) is true if either \(P\) is true or \(Q\) is true or both are true.

  • When \(P = T\) and \(Q = T\), \(P\vee Q=T\).
  • When \(P = T\) and \(Q = F\), \(P\vee Q=T\).
  • When \(P = F\) and \(Q = T\), \(P\vee Q=T\).
  • When \(P = F\) and \(Q = F\), \(P\vee Q=F\).

Step3: Calculate \(P\wedge Q\) values

The conjunction \(P\wedge Q\) is true only when both \(P\) and \(Q\) are true.

  • When \(P = T\) and \(Q = T\), \(P\wedge Q=T\).
  • When \(P = T\) and \(Q = F\), \(P\wedge Q=F\).
  • When \(P = F\) and \(Q = T\), \(P\wedge Q=F\).
  • When \(P = F\) and \(Q = F\), \(P\wedge Q=F\).

Step4: Calculate \(

eg(P\wedge Q)\) values
Negation of \(P\wedge Q\).

  • When \(P\wedge Q=T\), \(

eg(P\wedge Q)=F\).

  • When \(P\wedge Q=F\), \(

eg(P\wedge Q)=T\).

Step5: Calculate \((P\vee Q)\wedge

eg(P\wedge Q)\) values
The conjunction of \(P\vee Q\) and \(
eg(P\wedge Q)\).

  • When \(P\vee Q = T\) and \(

eg(P\wedge Q)=F\) (i.e., \(P = T\), \(Q = T\)), \((P\vee Q)\wedge
eg(P\wedge Q)=F\).

  • When \(P\vee Q = T\) and \(

eg(P\wedge Q)=T\) (i.e., \(P = T\), \(Q = F\)), \((P\vee Q)\wedge
eg(P\wedge Q)=T\).

  • When \(P\vee Q = T\) and \(

eg(P\wedge Q)=T\) (i.e., \(P = F\), \(Q = T\)), \((P\vee Q)\wedge
eg(P\wedge Q)=T\).

  • When \(P\vee Q = F\) and \(

eg(P\wedge Q)=T\) (i.e., \(P = F\), \(Q = F\)), \((P\vee Q)\wedge
eg(P\wedge Q)=F\).

The truth - table is as follows:

\(P\)\(Q\)\(P\vee Q\)\(P\wedge Q\)\(

eg(P\wedge Q)\) | \((P\vee Q)\wedge
eg(P\wedge Q)\) |

\(T\)\(T\)\(T\)\(T\)\(F\)\(F\)
\(T\)\(F\)\(T\)\(F\)\(T\)\(T\)
\(F\)\(T\)\(T\)\(F\)\(T\)\(T\)
\(F\)\(F\)\(F\)\(F\)\(T\)\(F\)

Answer:

The truth - table for \((P\vee Q)\wedge
eg(P\wedge Q)\) is shown above.