consider $8x^2 - 48x = -104$.

write the equation so that

$a = 1$: $x^2 + \quadx = \quad$

Question

consider $8x^2 - 48x = -104$.

write the equation so that

$a = 1$: $x^2 + \quadx = \quad$

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Solving Quadratic Equations" ], "new_concepts": [ "Completing the Square Steps" ], "current_concepts": [ "Solving Quadratic Equations", "Completing the Square Steps" ] } ## Divide the entire equation by the leading coefficient $$ \begin{aligned} \frac{8x^2 - 48x}{8} &= \frac{-104}{8} \ x^2 - 6x &= -13 \end{aligned} $$ ## Match with the target template $$ \begin{aligned} x^2 + (-6)x &= -13 \end{aligned} $$ Consider $8x^2 - 48x = -104$. Write the equation so that $a = 1$: $x^2 +$ -6$x =$ -13 { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Completing the Square" ] }

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QUESTION IMAGE

Question

Explanation:

Divide the entire equation by the leading coefficient

Match with the target template

Answer: