Question

consider the nuclear equation below.

$_{86}^{222}rn\longrightarrow_{?}^{218}po + _{2}^{4}he$

which is the missing value that will balance the equation?
84
86
88
90

Explanation:

Step1: Recall nuclear - equation balance rule

In a nuclear equation, the sum of atomic numbers on the left - hand side must equal the sum of atomic numbers on the right - hand side.

Step2: Identify atomic numbers

The atomic number of $^{222}_{86}Rn$ is 86, and the atomic number of $^{4}_{2}He$ is 2. Let the atomic number of $^{218}_{?}Po$ be $x$.

Step3: Set up the equation

We have the equation $86=x + 2$.

Step4: Solve for $x$

Subtract 2 from both sides of the equation: $x=86 - 2=84$.

Answer:

A. 84