Question

consider a new cross. this one will require you to think a little more about the genotypes of the parents. y=yellow, y=green
a heterozygous yellow seeded plant is crossed
with a homozygous green seeded plant.

1. establish the genotypes _ × _

of the parents:

1. set up the

square

1. determine the phenotypic percentages:

___ % yellow
___ % green

Explanation:

Question 11

Step1: Identify heterozygous parent

Heterozygous means having two different alleles. For yellow (dominant, Y) and green (recessive, y), heterozygous yellow is $Yy$.

Step2: Identify homozygous parent

Homozygous green (recessive) has two same alleles, so it's $yy$.

Step1: Determine gametes

Heterozygous parent ($Yy$) produces gametes $Y$ and $y$. Homozygous parent ($yy$) produces gametes $y$ and $y$.

Step2: Set up Punnett square

	Y	y
y	Yy	yy

Step1: Count phenotypes

From Punnett square: $Yy$ (yellow) and $yy$ (green). There are 2 $Yy$ and 2 $yy$.

Step2: Calculate percentages

Total offspring: 4. Yellow: $\frac{2}{4} \times 100 = 50\%$. Green: $\frac{2}{4} \times 100 = 50\%$.

Answer:

$Yy$ × $yy$

Question 12