Question

consider the following function.
h(x)=\frac{7}{4}x^{3}
step 2 of 2: find two points on the graph of this function, other than the origin, that fit within the given (-10,10) by (-10,10) grid. express each coordinate as an integer or simplified fraction, or round to four decimal places as necessary.

Explanation:

Step1: Choose an x - value

Let's choose \(x = 1\).

Step2: Calculate the corresponding y - value

Substitute \(x = 1\) into \(h(x)=\frac{7}{4}x^{3}\), then \(h(1)=\frac{7}{4}(1)^{3}=\frac{7}{4}=1.75\). So one point is \((1,1.75)\).

Step3: Choose another x - value

Let's choose \(x = 2\).

Step4: Calculate the corresponding y - value

Substitute \(x = 2\) into \(h(x)=\frac{7}{4}x^{3}\), then \(h(2)=\frac{7}{4}(2)^{3}=\frac{7}{4}\times8 = 14\). So another point is \((2,14)\).

Answer:

\((1,1.75)\), \((2,14)\)