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Question
consider the data shown below.
6, 8, 0, 2, 2, 8, 7, 8, 4, 8, 6, 3, 8, 2, 0, 8, 2, 3, 8
which measure of center would best describe a typical value of the data set? why?
would be better,
because the data distribution is
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0 1 2 3 4 5 6 7 8
First, we analyze the data set: 6, 8, 0, 2, 2, 8, 7, 8, 4, 8, 6, 3, 8, 2, 0, 8, 2, 3, 8. We count the frequency of each number: 0 appears 2 times, 2 appears 4 times, 3 appears 2 times, 4 appears 1 time, 6 appears 2 times, 7 appears 1 time, 8 appears 6 times. The mode (the most frequent value) is 8, which occurs 6 times. The data has a high frequency of 8, so the distribution is skewed? Wait, no, actually, when there's a mode with a high frequency, but let's check the mean and median. Wait, the mode is a measure of center. Wait, but let's see the data: many 8s, some 2s, 0s, 3s, 6s, etc. Wait, the mode is 8, but also, let's check the median. Wait, maybe the mode is the best? Wait, no, wait: the data has a lot of 8s, so the distribution is not symmetric. Wait, actually, the mode is the most frequent, but maybe the median? Wait, no, let's list the data in order: 0, 0, 2, 2, 2, 2, 3, 3, 4, 6, 6, 7, 8, 8, 8, 8, 8, 8. Wait, wait, the data has 19 numbers? Wait, original data: 6,8,0,2,2,8,7,8,4,8,6,3,8,2,0,8,2,3,8. Let's count: 1 (6), 2 (8), 3 (0), 4 (2), 5 (2), 6 (8), 7 (7), 8 (8), 9 (4), 10 (8), 11 (6), 12 (3), 13 (8), 14 (2), 15 (0), 16 (8), 17 (2), 18 (3), 19 (8). So ordered: 0,0,2,2,2,2,3,3,4,6,6,7,8,8,8,8,8,8,8? Wait, no, 19 numbers: positions 1 - 19. The median is the 10th term (since (19+1)/2 = 10). The 10th term: let's list them in order:
0, 0,
2, 2, 2, 2,
3, 3,
4,
6, 6,
7,
8, 8, 8, 8, 8, 8, 8.
Wait, let's count:
1: 0
2: 0
3: 2
4: 2
5: 2
6: 2
7: 3
8: 3
9: 4
10: 6
11: 6
12: 7
13: 8
14: 8
15: 8
16: 8
17: 8
18: 8
19: 8
So the median is the 10th term, which is 6? Wait, no, wait, 19 numbers: the median is the (19+1)/2 = 10th term. So 0 (1), 0 (2), 2 (3), 2 (4), 2 (5), 2 (6), 3 (7), 3 (8), 4 (9), 6 (10). Yes, so median is 6. The mean: sum all numbers. Let's calculate sum: 02 + 24 + 32 + 41 + 62 + 71 + 86. So 0 + 8 + 6 + 4 + 12 + 7 + 48 = 8+6=14, 14+4=18, 18+12=30, 30+7=37, 37+48=85. Wait, sum is 85? Wait, no, wait: 0 appears 2 times: 02=0. 2 appears 4 times: 24=8. 3 appears 2 times: 32=6. 4 appears 1 time: 41=4. 6 appears 2 times: 62=12. 7 appears 1 time: 71=7. 8 appears 6 times: 86=48. Now sum: 0+8=8, +6=14, +4=18, +12=30, +7=37, +48=85. Number of data points: 2+4+2+1+2+1+6=18? Wait, 2+4=6, +2=8, +1=9, +2=11, +1=12, +6=18. Oh, I miscounted earlier: 18 data points. So ordered data: 0,0,2,2,2,2,3,3,4,6,6,7,8,8,8,8,8,8. Now, median is the average of the 9th and 10th terms (since 18 is even: (18/2)=9th and 10th). 9th term: 4, 10th term: 6. So median is (4+6)/2=5. Mean: 85/18 ≈4.72. But the mode is 8 (appears 6 times), 2 (appears 4 times). Wait, the data has a lot of 8s, so the distribution is skewed towards 8? Wait, no, the mean is around 4.7, median 5, mode 8. So the data has a mode (8) with a high frequency, so the measure of center that best describes a typical value is the mode? Wait, no, maybe the median? Wait, no, the question is which measure of center: mean, median, or mode. Wait, the data has a mode (8) which is the most frequent, but also, the data has a lot of 8s, so the distribution is not symmetric. Wait, but maybe the mode is the best? Wait, no, let's check the frequency: 8 appears 6 times, which is more than any other number. So the mode is 8. But also, the data has a skewed distribution? Wait, no, the mean is lower than the median, which is lower than the mode, so it's a right-skewed distribution (tail to the right, but wait, mode is highest, mean lowest). Wait, right-skewed: mean < median < mode? No, left-skewed is mean < median < mode. Right-skewed is mode < median < mean. Wait, in o…
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Mode would be better, because the data distribution is skewed (or has a mode with high frequency, or not symmetric).
(Note: The exact answer may depend on the options, but based on the data, the mode is the most frequent value (8, 6 times), so mode is the best measure of center here, and the distribution is skewed (left-skewed) or has a mode with high frequency.)