Question

compute: ( z = ( sqrt { x + y } ) ^ { 3 } )
1 // your code will be tested with x = 3 and y = 5, and other values for x and y
2 let x = 3;
3 let y = 5;
4 let z = / your code goes here / ;
5
6 // output z with two decimal places
7 console.log(z.tofixed(2));
exploring further:

• math object (mdn)
• introduction to randomness and random numbers

Explanation:

Step1: Calculate \(x + y\)

\(x + y=3 + 5=8\)

Step2: Calculate \(\sqrt{x + y}\)

In JavaScript, the square - root function is Math.sqrt(). So \(\sqrt{8}=Math.sqrt(8)\approx2.8284\)

Step3: Calculate \((\sqrt{x + y})^3\)

In JavaScript, the exponentiation can be done using the operator. So \(z = Math.sqrt(x + y)3\)

When \(x = 3\) and \(y = 5\), \(z=( \sqrt{3 + 5})^3=( \sqrt{8})^3\approx2.8284^3\approx22.6274\)

Answer:

let z = Math.sqrt(x + y) ** 3;