Question

compound probabilities-mutually exclusive events

a box of colored pencils has 7 red, 3 green, 6 blue, and 8 yellow. a pencil is drawn at random. what is the probability that the pencil is red or green?

\\(p(\text{red or green}) = \quad\\%\\)

round your answer to the nearest whole percent.

Explanation:

Calculate total number of pencils

$$ N = 7 + 3 + 6 + 8 = 24 $$

Find favorable outcomes for red or green

$$ n(\text{Red or Green}) = 7 + 3 = 10 $$

Compute probability as a percentage

$$ P(\text{Red or Green}) = \frac{10}{24} = \frac{5}{12} \approx 0.4167 \approx 42\% $$

Answer:

A box of colored pencils has 7 red, 3 green, 6 blue, and 8 yellow. A pencil is drawn at random. What is the probability that the pencil is red or green?

\(P(\text{Red or Green}) =\) <blank>42</blank>%