Question

complete the punnett square to show all possible genotypes of the offspring from a cross between two holsteins: one heterozygous with red - to - black spots and one with black spots carrying a red - to - black allele. write the genotypes so that dominant alleles come before recessive alleles.

Explanation:

Step1: Determine the genotypes of the parents

The heterozygous parent with red - to - black spots has the genotype \(M m^{r}\). The parent with black spots carrying a red - to - black allele has the genotype \(m^{r}m\).

Step2: Fill in the Punnett square

For the row labeled \(m^{r}\):

• When combining \(m^{r}\) (from the second parent) with \(M\) (from the first parent), the genotype is \(M m^{r}\).
• When combining \(m^{r}\) (from the second parent) with \(m^{r}\) (from the first parent), the genotype is \(m^{r}m^{r}\).

For the row labeled \(m\):

• When combining \(m\) (from the second parent) with \(M\) (from the first parent), the genotype is \(M m\).
• When combining \(m\) (from the second parent) with \(m^{r}\) (from the first parent), the genotype is \(m^{r}m\).

Answer:

The completed Punnett square has the following genotypes:

	\(M\)	\(m^{r}\)
\(m\)	\(M m\)	\(m^{r}m\)