QUESTION IMAGE
Question
complete the proof that \\(\overline{ux} \cong \overline{sw}\\).
| statement | reason |
|---|---|
| 2. \\(\overline{xy} \cong \overline{vw}\\) | given |
| 3. \\(\angle y \cong \angle v\\) | given |
| 4. \\(wy = xy + wx\\) | additive property of length |
| 5. \\(vx = vw + wx\\) | additive property of length |
| 6. \\(wy = vw + wx\\) | substitution |
| 7. \\(vx = wy\\) | |
| 8. \\(\triangle swy \cong \triangle uxv\\) | asa |
| 9. \\(\overline{ux} \cong \overline{sw}\\) | cpctc |
Step1: Analyze Statements 5 and 6
From Statement 5: \( VX = VW + WX \) and Statement 6: \( WY = VW + WX \).
Step2: Apply Transitive Property
If two quantities are both equal to the same third quantity, they are equal to each other. So since \( VX = VW + WX \) and \( WY = VW + WX \), we can conclude \( VX = WY \) by the Transitive Property of Equality (or Substitution, but here it's the transitive property as both equal \( VW + WX \)).
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Transitive Property of Equality (or Substitution, recognizing both equal \( VW + WX \))