Question

complete the following statement. use the integers that are closest to the number in the middle.
\boxed{} < \sqrt3{55} < \boxed{}

Explanation:

Step1: Find cube of 3

$3^3 = 27$

Step2: Find cube of 4

$4^3 = 64$

Step3: Compare with $\sqrt[3]{55}$

Since $27 < 55 < 64$, taking cube roots gives $3 < \sqrt[3]{55} < 4$.

Answer:

$3 < \sqrt[3]{55} < 4$