Question

complementary and supplementary angles
calculating angle measur
m
(10y + 6)° (8y - 6)°
j k l
m∠m k l =
74
114
127

Explanation:

Step1: Set up equation

Since $\angle{JKM}$ and $\angle{MKL}$ are supplementary, $(10y + 6)+(8y - 6)=180$.

Step2: Simplify equation

$10y+6 + 8y-6=180$, which simplifies to $18y=180$.

Step3: Solve for y

$y=\frac{180}{18}=10$.

Step4: Find $\angle{MKL}$

Substitute $y = 10$ into the expression for $\angle{MKL}$: $8y-6=8\times10 - 6=80 - 6=74$.

Answer:

74