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comparing relative frequency tables using the data below, eve created a…

Question

comparing relative frequency tables
using the data below, eve created a conditional relative frequency table by column and bob created a conditional relative frequency table by row.

enjoys dancingdoes not enjoy dancingtotal
girls401050
total6040100

which statements are true? check all that apply.

  • ☐ based on both tables, there is no association between gender and enjoying dancing.
  • ☐ eve’s table shows that those who enjoy dancing are likely girls.
  • ☐ bob’s table shows that boys are likely to not enjoy dancing.
  • ☐ the two tables will be identical since boys and girls have the same total number.
  • ☐ the percentage of someone being a girl, given that the person enjoys dancing is lower than the percentage that someone enjoys dancing, given that the person is a girl.

Explanation:

To solve this, we analyze each statement using the given data:

1. "Based on both tables, there is no association between gender and enjoying dancing."
  • For Eve (column - conditional):
  • % of boys who enjoy dancing: $\frac{20}{60} \approx 33.3\%$; % of girls who enjoy dancing: $\frac{40}{60} \approx 66.7\%$.
  • For Bob (row - conditional):
  • % of boys who enjoy dancing: $\frac{20}{50} = 40\%$; % of boys who don’t: $\frac{30}{50} = 60\%$.
  • % of girls who enjoy dancing: $\frac{40}{50} = 80\%$; % of girls who don’t: $\frac{10}{50} = 20\%$.
  • Since these percentages differ, there is an association. So this statement is false.
2. "Eve’s table shows that those who enjoy dancing are likely girls."
  • Eve’s table (column - conditional) for “Enjoys Dancing”:
  • % of boys: $\frac{20}{60} \approx 33.3\%$; % of girls: $\frac{40}{60} \approx 66.7\%$.
  • Since 66.7% (girls) > 33.3% (boys), those who enjoy dancing are more likely girls. This statement is true.
3. "Bob’s table shows that boys are likely to not enjoy dancing."
  • Bob’s table (row - conditional) for “Boys”:
  • % who enjoy dancing: $\frac{20}{50} = 40\%$; % who don’t: $\frac{30}{50} = 60\%$.
  • Since 60% (don’t enjoy) > 40% (enjoy), boys are likely to not enjoy dancing. This statement is true.
4. "The two tables will be identical since boys and girls have the same total number."
  • Eve’s table (column - conditional) focuses on column totals (60, 40), while Bob’s (row - conditional) focuses on row totals (50, 50).
  • For example, Eve’s “Enjoys Dancing” column: $\frac{20}{60}, \frac{40}{60}$; Bob’s “Boys” row: $\frac{20}{50}, \frac{30}{50}$. These are different. So the tables are not identical. This statement is false.
5. "The percentage of someone being a girl, given that the person enjoys dancing is lower than the percentage that someone enjoys dancing, given that the person is a girl."
  • Let’s calculate both:
  • “Girl, given enjoys dancing” (Eve’s table): $\frac{40}{60} \approx 66.7\%$.
  • “Enjoys dancing, given girl” (Bob’s table): $\frac{40}{50} = 80\%$.
  • $66.7\% < 80\%$, so this statement is true.

Answer:

The true statements are:

  • Eve’s table shows that those who enjoy dancing are likely girls.
  • Bob’s table shows that boys are likely to not enjoy dancing.
  • The percentage of someone being a girl, given that the person enjoys dancing is lower than the percentage that someone enjoys dancing, given that the person is a girl.

(In boxed form for the selected options, assuming the options are labeled as follows:
A. Based on both tables...
B. Eve’s table shows...
C. Bob’s table shows...
D. The two tables will...
E. The percentage of someone...

Then the answer is: B. Eve’s table shows that those who enjoy dancing are likely girls., C. Bob’s table shows that boys are likely to not enjoy dancing., E. The percentage of someone being a girl, given that the person enjoys dancing is lower than the percentage that someone enjoys dancing, given that the person is a girl.)