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comparing measures of center and variability finding the mean absolute …

Question

comparing measures of center and variability
finding the mean absolute deviation
what is the mean absolute deviation of robins scores?
mad = \frac{8 + 1+5 + 0+12}{5}
robins scores 99 108 102 107 119
distance from the mean 8 1 5 0 12

Explanation:

Step1: Sum the values

$$8 + 1+5 + 0+12$$
$$= (8 + 1)+(5 + 0)+12$$
$$=9 + 5+12$$
$$=14 + 12$$
$$=26$$

Step2: Divide by the number of data points

The formula for MAD is \(\text{MAD}=\frac{\sum_{i = 1}^{n}|x_{i}-\bar{x}|}{n}\), here \(n = 5\) (since there are 5 scores).
\(\text{MAD}=\frac{26}{5}=5.2\)

Answer:

\(5.2\)