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(a) a company used 24.8 kilograms (kg) of molten steel to make 4 go - k…

Question

(a) a company used 24.8 kilograms (kg) of molten steel to make 4 go - kart engines. cooling the engines after the manufacturing process required 8 liters of water for each kilogram of steel. the company would like to make 7 go - kart engines using the same amount of steel in each engine as last time. fill in the blanks below. then use the diagram to show the steel and water needed to make 7 go - kart engines. amount of steel used for each engine: \square kg amount of water used for each engine: \square liters (diagram: a table with two columns labeled 1 engine each, grouped as 2 engines, with rows for kg and liters) (b) how much water is needed to make 7 go - kart engines? \square liters

Explanation:

Step1: Find steel per engine

To find the amount of steel per engine, divide total steel by number of engines. Total steel is 24.8 kg, number of engines is 4. So, $24.8 \div 4 = 6.2$ kg per engine.

Step2: Find water per engine

Water per kg of steel is 8 liters. Since each engine uses 6.2 kg of steel, water per engine is $6.2 \times 8 = 49.6$ liters.

Step3: Find water for 7 engines

First, find total steel for 7 engines: $6.2 \times 7 = 43.4$ kg. Then, water is $43.4 \times 8 = 347.2$ liters. Or, since water per engine is 49.6, for 7 engines: $49.6 \times 7 = 347.2$ liters.

Part (a) Blanks:
  • Amount of steel per engine: $6.2$ kg
  • Amount of water per engine: $49.6$ liters
Part (b) Water for 7 engines:

Using water per engine (49.6) times 7: $49.6 \times 7 = 347.2$ liters.

Answer:

s:
(a) Amount of steel used for each engine: $\boldsymbol{6.2}$ kg
Amount of water used for each engine: $\boldsymbol{49.6}$ liters
(b) Water needed for 7 engines: $\boldsymbol{347.2}$ liters