Question

in $delta jkl$, $j = 79$ cm, $k = 74$ cm and $l = 65$ cm. find the area of $delta jkl$ to the nearest square centimeter.

Explanation:

Step1: Calculate semi - perimeter

Let \(a = 79\), \(b = 74\), \(c = 65\). The semi - perimeter \(s=\frac{a + b + c}{2}=\frac{79+74 + 65}{2}=\frac{218}{2}=109\) cm.

Step2: Use Heron's formula

Heron's formula for the area of a triangle is \(A=\sqrt{s(s - a)(s - b)(s - c)}\). Substitute \(s = 109\), \(a = 79\), \(b = 74\), \(c = 65\) into the formula:

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Answer:

2244 \(cm^{2}\)