Question

in a closed system, an object with a mass of 10 kg moves at a velocity of 5.4 m/s. it collides with a second object that has a mass of 12 kg and that is moving in the opposite direction with a velocity of 3.5 m/s. what is the total momentum of the system after the collision? (1 point) 12 kg - m/s 42 kg - m/s 54 kg - m/s 66 kg - m/s

Explanation:

Step1: Calculate the momentum of the first object

Momentum formula \(p = mv\). For the first object, \(m_1=10\space kg\), \(v_1 = 5.4\space m/s\). So \(p_1=m_1v_1=10\times5.4 = 54\space kg\cdot m/s\)

Step2: Calculate the momentum of the second object

For the second object, \(m_2 = 12\space kg\), \(v_2=- 3.5\space m/s\) (opposite direction). So \(p_2=m_2v_2=12\times(-3.5)=-42\space kg\cdot m/s\)

Step3: Calculate the total initial momentum

In a closed system, total momentum is conserved. Total initial momentum \(p_{total}=p_1 + p_2\). \(p_{total}=54+( - 42)=12\space kg\cdot m/s\)

Answer:

12 kg - m/s