Question

a circular garden with a radius of 8 feet is surrounded by a circular path with a width of 3 feet. what is the approximate area of the path alone? use 3.14 for π. 172.70 ft² 178.98 ft² 200.96 ft² 379.94 ft²

Explanation:

Step1: Find outer - radius

The radius of the garden is $r = 8$ feet and the width of the path is 3 feet. So the outer - radius $R=r + 3=8 + 3=11$ feet.

Step2: Calculate area of outer - circle

The area of a circle is $A=\pi R^{2}$. Using $\pi = 3.14$ and $R = 11$ feet, we have $A_{outer}=3.14\times11^{2}=3.14\times121 = 379.94$ square feet.

Step3: Calculate area of inner - circle

The inner - circle is the garden with radius $r = 8$ feet. So $A_{inner}=3.14\times8^{2}=3.14\times64 = 200.96$ square feet.

Step4: Calculate area of the path

The area of the path $A = A_{outer}-A_{inner}$. So $A=379.94−200.96 = 178.98$ square feet.

Answer:

178.98 ft²