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Question
- circle the line that represents 12 = 3x + 4y. line a line b line c show or explain how you know. 4. solve 15x + 3y = 2 for y.
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To solve \( 15x + 3y = 2 \) for \( y \):
- Subtract \( 15x \) from both sides:
\( 3y = -15x + 2 \)
- Divide every term by \( 3 \):
\( y = -5x + \frac{2}{3} \)
(For the graphing part, to identify \( 12 = 3x + 4y \), rewrite it in slope - intercept form (\( y=mx + b \)):
- Subtract \( 3x \) from both sides: \( 4y=-3x + 12 \)
- Divide by \( 4 \): \( y =-\frac{3}{4}x+3 \). The line with slope \( -\frac{3}{4} \) and \( y \) - intercept \( 3 \) (crosses \( y \) - axis at \( (0,3) \)) is the one representing \( 12 = 3x + 4y \).)