Question

in circle k with m∠jkl = 84° and jk = 6, find the area of sector jkl. round to the nearest hundredth.

Explanation:

Step1: Recall the formula for the area of a sector

The formula for the area of a sector of a circle is \(A=\frac{\theta}{360}\times\pi r^{2}\), where \(\theta\) is the central angle and \(r\) is the radius of the circle.

Step2: Identify the values of \(\theta\) and \(r\)

Given that \(\theta = m\angle{JKL}=84^{\circ}\) and \(r = JK = 6\).

Step3: Substitute the values into the formula

Substitute \(\theta = 84\) and \(r = 6\) into the formula \(A=\frac{\theta}{360}\times\pi r^{2}\).

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Step4: Calculate the numerical value

Using \(\pi\approx3.14159\), we have \(A = 8.4\times3.14159\approx26.39\)

Answer:

\(26.39\)