Question

cinnabar eyes is a sex - linked recessive characteristic in fruit flies in which the eyes of the individual are lighter in color than the normal wild - type red color. if a female having cinnabar eyes is crossed with a wild - type male, what percentage of the f1 males will have cinnabar eyes? 100% 0% 50% 25%

Explanation:

Step1: Determine the genotypes

Let \(X^{c}\) represent the recessive allele for cinnabar eyes and \(X^{+}\) represent the dominant allele for wild - type red eyes. Females have two X chromosomes, and males have one X and one Y chromosome.
The female with cinnabar eyes has the genotype \(X^{c}X^{c}\). The wild - type male has the genotype \(X^{+}Y\).

Step2: Analyze the cross

When \(X^{c}X^{c}\) (female) is crossed with \(X^{+}Y\) (male), the possible gametes from the female are all \(X^{c}\), and the possible gametes from the male are \(X^{+}\) and \(Y\).
Using the Punnett square method:

Female gametes \(X^{c}\)	Male gametes \(X^{+}\)	Male gametes \(Y\)

For the F1 males, the genotype is \(X^{c}Y\) (since males inherit the X chromosome from the mother and Y from the father).

Answer:

100%