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in cell reproduction, there are 2 cells present after day 1, 4 after da…

Question

in cell reproduction, there are 2 cells present after day 1, 4 after day 2, 8 after day 3 and so on. write an exponential equation that could be used to find out how many cells there will be on the nth day. how many cells will there be on the 20th day?

Explanation:

Step1: Identify the pattern

We observe that the number of cells is \(2 = 2^{1}\) on day 1, \(4=2^{2}\) on day 2, \(8 = 2^{3}\) on day 3. So, the general formula for the number of cells \(y\) on day \(n\) is \(y = 2^{n}\).

Step2: Substitute \(n = 200\) into the formula

When \(n = 200\), we have \(y=2^{200}\).

Answer:

The number of cells on the \(200^{th}\) day is \(2^{200}\)