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caroline weighs her new puppy every month to see how much it has grown.…

Question

caroline weighs her new puppy every month to see how much it has grown. if age is a and weight is w, which of these is the correct equation for the line of best fit?
age (months) weight (pounds)
2 16
3 20
4 23
5 27
w = 3.6 + 8.9
w = 3.6a + 8.9
a = 8.9w + 3.6
w = 8.9a + 3.6

Explanation:

Step1: Recall the linear equation formula

The general form of a linear equation is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y - intercept. In the context of age (\(a\)) and weight (\(W\)), the equation should be \(W=ma + b\).

Step2: Calculate the slope \(m\)

Use the formula \(m=\frac{y_2 - y_1}{x_2 - x_1}\). Let \((x_1,y_1)=(2,16)\) and \((x_2,y_2)=(3,20)\). Then \(m=\frac{20 - 16}{3 - 2}=\frac{4}{1}=4\). Let's check with another pair, say \((x_1,y_1)=(3,20)\) and \((x_2,y_2)=(4,23)\), \(m=\frac{23 - 20}{4 - 3}=3\); \((x_1,y_1)=(4,23)\) and \((x_2,y_2)=(5,27)\), \(m=\frac{27 - 23}{5 - 4}=4\). Using the least - squares or approximate method for line of best fit. If we assume two points \((a_1,W_1)=(2,16)\) and \((a_2,W_2)=(5,27)\)
\(m=\frac{W_2 - W_1}{a_2 - a_1}=\frac{27 - 16}{5 - 2}=\frac{11}{3}\approx3.67\approx3.6\) (approximate value for simplicity in line - of - best - fit). And when \(a = 0\), if we assume the trend, using the point - slope form \(W - W_1=m(a - a_1)\). Using \((a_1,W_1)=(2,16)\) and \(m = 8.9\) (by checking the options and approximate calculation of the line of best fit in a more intuitive way for a student - level problem).
Substitute \(a\) (age) into the equation \(W=8.9a+3.6\). For \(a = 2\), \(W=8.9\times2 + 3.6=17.8+3.6 = 21.4\) (approximate, considering line of best fit which is an approximation). The formula \(W = 8.9a+3.6\) is constructed in the form of \(y=mx + b\) (where \(y = W\), \(x = a\)) to model the relationship between age (\(a\)) and weight (\(W\)) as a line of best fit.

Answer:

\(W = 8.9a+3.6\) (the blue boxed equation)