QUESTION IMAGE
Question
a car traveled 180 miles at a constant rate.
a. complete the table to show the rate at which the car was traveling if it completed the same distance in each number of hours.
| travel time (hours) | rate of travel (miles per hour) |
|---|---|
| 4.5 | |
| 3 | |
| 2.25 |
b. which equation would make it easy to find the rate at which the car was traveling in miles per hour ( r ), if it traveled for ( t ) hours? equation
Step1: Recall the formula for rate
The formula relating distance \( d \), rate \( r \), and time \( t \) is \( d = r\times t \), so we can solve for rate \( r \) as \( r=\frac{d}{t} \). Here, the distance \( d = 180 \) miles.
Step2: Calculate rate for 5 hours
For \( t = 5 \) hours, substitute into \( r=\frac{d}{t} \). So \( r=\frac{180}{5}=36 \) miles per hour.
Step3: Calculate rate for 4.5 hours
For \( t = 4.5 \) hours, \( r=\frac{180}{4.5} \). We can rewrite \( 4.5=\frac{9}{2} \), so \( r = 180\div\frac{9}{2}=180\times\frac{2}{9} = 40 \) miles per hour.
Step4: Calculate rate for 3 hours
For \( t = 3 \) hours, \( r=\frac{180}{3}=60 \) miles per hour.
Step5: Calculate rate for 2.25 hours
For \( t = 2.25 \) hours, \( 2.25=\frac{9}{4} \), so \( r = 180\div\frac{9}{4}=180\times\frac{4}{9}=80 \) miles per hour.
Step6: Find the equation for part b
From \( d = r\times t \) and \( d = 180 \), we can solve for \( r \) to get \( r=\frac{180}{t} \) or \( r\times t=180 \) (either form is acceptable, but \( r=\frac{180}{t} \) is more direct for finding \( r \) given \( t \)).
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Part a Table:
| Travel Time (hours) | Rate of Travel (miles per hour) |
|---|---|
| 4.5 | 40 |
| 3 | 60 |
| 2.25 | 80 |
Part b Equation:
\( r=\frac{180}{t} \) (or \( rt = 180 \))